Question

find the coordinates of a point which divides A (-3,8) and B( 3,8) in the ratio 1:2.
a)(-4,4). b)(0,0).
c)(3,4).
d)(-1,8).​

Answer 1

$\textbf{Given:}$

$\textsf{Points are A(-3,8) and B(3,8)}$

$\textbf{To find:}$

$\textsf{The co-ordinates of the point which divides AB in the ratio 1:2}$

$\textbf{Solution:}$

$\textsf{By Section formula, the co-ordinates of the point which}$

$\textsf{divides AB internally in the ratio m:n are}$

$\mathsf{\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)}$

$\mathsf{\left(\dfrac{1(3)+2(-3)}{1+2},\dfrac{1(8)+2(8)}{1+2}\right)}$

$\mathsf{\left(\dfrac{3-6}{3},\dfrac{8+16}{3}\right)}$

$\mathsf{\left(\dfrac{-3}{3},\dfrac{24}{8}\right)}$

$\implies\boxed{\mathsf{(-1,3)}}$

$\textbf{Answer:}$

$\textsf{Option (d) is correct}$

Find more:

The point Q divides segment joining A (3, 5) and B (7, 9) in the ratio 2 : 3. Find the X-coordinate of Q.

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