Question

find the coordinates of the centre of the circle 3xsquare+3ysquare-4x+8y-2=0

Answer 1

Answer:

$3 {x}^{2} + 3 {y}^{2} - 4x + 8y - 2 = 0 \\ x(3x + 3y - 4 + 8) = 0 \\3x + 3y + 4 = 0 \\ 3(x + y) = - 4 \\ x + y = \frac{ - 4}{3}$

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Answer 2

The equation for a circle with centre coordinates (a, b) and radius r is

\((x-a)^{2} + (y-b)^{2} = r^{2}\)

Expanding the above equation, we have