Find the coordinates of the centre of the circle passing through the points (14,6) , (9,1) and (4,6
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Step-by-step explanation:
Let O(x,y) is the center of the circle and A(6.−6),B(3,−7) and C(3,3)are the points on the circumference of the circle.
∴OA=(x1−x2)2+(y1−y2)2
⇒OA=(x−6)2+(y+6)2
⇒OB=(x−3)2+(y+7)2
⇒OC=(x−3)3+(y−3)2
∵ Radii of the circle are equal
∴OA=OB
⇒(x−6)2+(y+6)2=(x−3)2+(y+7)2
⇒x2+36−12x+y2+36+12y=x2+9−
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