Question

Find the coordinates of the centroid of a triangle whose vertices are (0 6) (8 12) and (8 0)

Answer 1

Answer:

Step-by-step explanation:

Coordinate of centroid=X1+X2+X3/3,Y1+Y2+Y3/3

=0+8+8/3,6+12+0/3

=16/3,18/3

=16/3,6

Answer 2

Answer:

$centroid \: of \: the \: triangle\\=(\frac{16}{3},6)$

Step-by-step explanation:

$vertices\: of\: a\:triangle\\ \:are \:(0,6),\:(8,12) \:and \:(8,0)$

$x_{1}=0,\:y_{1}=6;\\x_{2}=8,\:y_{2}=12;\\x_{3}=8,\:y_{3}=0;$

$The\: coordinates\:of\:the\\centroid \: are \\=\big(\frac{x_{1}+x_{2}+x_{3}}{3},\frac{y_{1}+y_{2}+y_{3}}{3}\big)\\=\big(\frac{0+8+8}{3},\frac{6+12+0}{3}\big)\\=\big(\frac{16}{3},\frac{18}{3}\big)\\=\big(\frac{16}{3},6\big)$

Therefore,

$centroid \: of \: the \: triangle\\=(\frac{16}{3},6)$

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