find the coordinates of the foci of the hyperbola y²-16x²=16.
Answers
Answered by
0
Step-by-step explanation:
We have, 16x
2
−9y
2
=576
⇒
36
x
2
−
64
y
2
=1
⇒
6
2
x
2
−
8
2
y
2
=1...(1)
On comparing equation (1) with the standard equation of hyperbola,
a
2
x
2
−
b
2
y
2
=1,
we obtain a=6,b=8⇒e=
1+
a
2
b
2
=
1+
36
64
=
3
5
Therefore, the coordinates of the foci are (±10,0)
The coordinates of the vertices are (±6,0)
Eccentricity e=
3
5
Length of latus rectum =
a
2b
2
=
6
2×64
=
3
64
Answered by
0
Step-by-step explanation:
i cant answer this sorry best of luck
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