Question

find the coordinates of the point which divides the line segment a b in the given ratio:A (m+n,m-n),B(m-n,m+n) ratio :m:n​

Answer 1

When a point C divides a segment AB in the ratio m:n, we use the section formula to find the coordinates of that point. The section formula has 2 types. These types depend on the position of point C. It can be present between the 2 points or outside the segment.

This is what section formula means
The answer of this question I don’t know but I can answer a similar question:

{[(mx2+nx1)/(m+n)],[(my2+ny1)/(m+n)]}

Breaking it down, the x coordinate is (mx2+nx1)/(m+n) and the y coordinate is (my2+ny1)/(m+n)

Section Formula for External Division

When the point P lies on the external part of the line segment, we use the section formula for the external division for its coordinates.



A point on the external part of the segment means when you extend the segment than its actual length the point lies there. Just as you see in the diagram above. The section formula for external division is,

P={[(mx2-nx1)/(m-n)],[(my2-ny1)/(m-n)]}

Breaking it down, the x coordinate is (mx2-nx1)/(m-n) and the y coordinate is (my2-ny1)/(m-n)