Question

find the coordinates of the point which
divides the line segment joining points
(-1,7) and (4,-3) in the ratio 2:3.​

Answer 1

Answer:

(1,3)

by point of tri section formula

Answer 2

Hello,

_______________

${\boxed{ \bold{Question:- }}}$

Find the coordinates of the point which divides the line segment joining points(-1,7) and (4,-3) in the ratio 2:3.

________________

${\boxed{ \bold{ Solution:- }}}$

➤ Given ratio:- 2:3 = m:n

➤ Co-ordinates of first point:- (-1,7) = (x1,y1)

➤ Co-ordinates of second point:- (4,-3) = (x2,y2)

_______________

$\texttt{ Using section formula,}$

$= > \frac{(mx2 + nx1)}{m + n} ,\frac{(my2 + ny1)}{m + n} \\ = > \frac{(2 \times4 + 3 \times - 1)}{2+ 3},\frac{(2 \times - 3 + 3 \times 7)}{2 + 3} \\ = > \frac{8 - 3}{5} , \frac{ - 6 + 21}{5} \\ = > \frac{5}{5} , \frac{15}{5} \\ = > (1,3)$

______________

Therefore, (1,3) is the solution.

______________

$\mathcal{ Be\: Brainly!}$