Math, asked by nichithamanju, 1 month ago

Find the coordinates of the point which
divides the line joining the points (3,-2) and
(5,6) in the
ratio
3:2

Answers

Answered by prachijadhav1113
1

Step-by-step explanation:

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Attachments:
Answered by tennetiraj86
2

Step-by-step explanation:

Given:-

The points (3,-2) and (5,6)

To find:-

Find the coordinates of the point which

divides the line joining the points (3,-2) and (5,6) in the ratio 3:2 ?

Solution:-

Given points are (3,-2) and (5,6)

Let (x1, y1)=(3,-2)=>x1=3 and y1=-2

Let (x2, y2)=(5,6)=>x2=5 and y2=6

Given ratio = 3:2

Let m1:m2 = 3:2=>m1=3 and m2=2

We know that

Section formula:-

The coordinates of the point P(x,y) which divides the linesegment joining the points (x1, y1) and

(x2, y2) in the ratio m1:m2 is

( {m1x2+m2x1}/(m1+m2) , {m1y2+ m2y1}/(m1+m2) )

On Substituting these values in the above formula

=> ( {(3)(5)+(2)(3)}/(3+2) , {(3)(6)+(2)(-2)}/(3+2) )

=> ( {15+6}/5 , {18-4}/5 )

=> (21/5 , 14/5 )

Answer:-

The coordinates of the point which divides the linesegment joining the given points in the ratio 3:2 is (21/5 , 14/5)

Used formulae:-

Section formula:-

The coordinates of the point P(x,y) which divides the linesegment joining the points (x1, y1) and

(x2, y2) in the ratio m1:m2 is

( {m1x2+m2x1}/(m1+m2) , {m1y2+ m2y1}/(m1+m2) )

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