Find the coordinates of the point which
divides the line joining the points (3,-2) and
(5,6) in the
ratio
3:2
Answers
Step-by-step explanation:
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Step-by-step explanation:
Given:-
The points (3,-2) and (5,6)
To find:-
Find the coordinates of the point which
divides the line joining the points (3,-2) and (5,6) in the ratio 3:2 ?
Solution:-
Given points are (3,-2) and (5,6)
Let (x1, y1)=(3,-2)=>x1=3 and y1=-2
Let (x2, y2)=(5,6)=>x2=5 and y2=6
Given ratio = 3:2
Let m1:m2 = 3:2=>m1=3 and m2=2
We know that
Section formula:-
The coordinates of the point P(x,y) which divides the linesegment joining the points (x1, y1) and
(x2, y2) in the ratio m1:m2 is
( {m1x2+m2x1}/(m1+m2) , {m1y2+ m2y1}/(m1+m2) )
On Substituting these values in the above formula
=> ( {(3)(5)+(2)(3)}/(3+2) , {(3)(6)+(2)(-2)}/(3+2) )
=> ( {15+6}/5 , {18-4}/5 )
=> (21/5 , 14/5 )
Answer:-
The coordinates of the point which divides the linesegment joining the given points in the ratio 3:2 is (21/5 , 14/5)
Used formulae:-
Section formula:-
The coordinates of the point P(x,y) which divides the linesegment joining the points (x1, y1) and
(x2, y2) in the ratio m1:m2 is
( {m1x2+m2x1}/(m1+m2) , {m1y2+ m2y1}/(m1+m2) )