Question

Find the coordinates of the point which divides the line segment joining the points (3,4) and (7,9) internally in he ratio 2:3.

Answer 1

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Answer 2

Answer:

The coordinates of point P are $(\frac{23}{5},6)$

Step-by-step explanation:

The line segment joining the points A(3,4) and B(7,9).

Let point P divides the line segment AB internally in he ratio 2:3.

The section formula is

$P=(\frac{x_2m+x_1n}{m+n}, \frac{y_2m+y_1n}{m+n})$

Using the section formula, we get

$P=(\frac{7(2)+3(3)}{2+3}, \frac{9(2)+4(3)}{2+3})$

$P=(\frac{23}{5}, \frac{30}{5})$

$P=(\frac{23}{5},6)$

Therefore the coordinates of point P are $(\frac{23}{5},6)$.