Question

find the coordinates of the point which divides the line segment joining points (1,-3) and (-3.9) in the ratio 1:3 internally

Answer 1

let the point G(x,y) divides SEG AB
in ratio 1:3
A(1,-3)=x1,y1 , B(-3,9)=x2,y2
m:n=1:3
by section formula
x=mx2+nx1/m+n y=my2+ny1/m+n
=1(-3)+3(1)/1+3 =1(9)+3(-3)/1+3
=-3+3/4 =9-9/4
=0/4. =0/4
=0. =0
the coordinates of point dividing line segment
AB in ratio 1:3 are G(x,y)=(0,0)
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