Find the coordinates of the points on Y-axis which are at a distance of 5√2 units
from the point (5,8).
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I am sure you are asking this question from ICSE class 9 specimen paper as we have Maths exam tomorrow. Let's answer
Step-by-step explanation:
Let point A(0,y)
B(5,8)
AB=√(5-0)²+(8-y)²
5√2=√5²-(8-y)²
50=25+64+y²-16y
SQUARING BOTH SIDES
y²-16y+39=0
y²-13y-3y+39=0
(y-13)(y-3)
y=13 or y=3
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