Find the cordinates of the point which ie equidistance from the points (-3,4) and (2,5) and lie on x axis
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A(-3,4) , B(2,5)
If third point lie on X-axis ,then
Let the point be C(x,0)
If AC=BC ,THEN
√[(x+3)²+(0-4)²] = √[(x-2)²+(0-5)²]
Cut both sides root
x²+9+6x+16=x²+4-4x+25
(x²+25) common on both side. it cut off
6x=4-4x
10x=4
x=2/5
Point C(2/5,0
If third point lie on X-axis ,then
Let the point be C(x,0)
If AC=BC ,THEN
√[(x+3)²+(0-4)²] = √[(x-2)²+(0-5)²]
Cut both sides root
x²+9+6x+16=x²+4-4x+25
(x²+25) common on both side. it cut off
6x=4-4x
10x=4
x=2/5
Point C(2/5,0
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