Question

find the cosecutive numbers whose squares have the sum 85
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Answer 1

Step-by-step explanation:

Let the no. be =x

its consecutive no. be = x+1

According to question =

x^2 +(x+1)^2=85

x^2 + (x^2+1+2x) =85              {(a+b)^2=a^2+b^2+2ab}

2x^2+2x+1-85=0

2x^2+2x-84=0

x^2+x-42=0

x^2+7x-6x-42=0

x(x+7) -6(x+7)=0

(x+7) (x-6)=0

x=-7 , x=6

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