Math, asked by Mehakuusharma, 1 year ago

find the cost of constructing a defence wall50×1×8m with stones each measuring 2.5 ×1.75×1 when 1÷8 of the wall is occupied by mortor

Answers

Answered by vimal123
0
only 7/8 part of the wall needs to be constructed. So,
volume of wall to be constructed=(50*1*8)*(7/8)
Now, No. of stone required=(50*1*7)/(2.5*1.75*1)=80
Now, total cost of construction of wall=80* cost of 1 stone.


Ps: Since you didnt mention cost of each stone.Hence this is the answer.
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