Math, asked by triptibhagat6868, 1 year ago

Find the cost of fencing a rectangular ground whose length and breath are in the ratio 4:3 and area is 768m square at the rate of rupees 25 per meter.​

Answers

Answered by Lily200
8

Answer:

Step-by-step explanation:

here

length = 4x

breadth  = 3x

area = 768 = l multiplied by b

area = 768 = 4x multiplied by 3x

768 =  12x^2

768/12 = x^2

64 = x^2

root of 64 =  x

x = 8

l= 4 multiplied by 8 = 32

b = 3 multiplied by 8 = 24

perimeter = 2( l+b )

= 2 ( 32 + 24 )

= 2 multiplied by 56

= 112 m

total cost = 112 multiplied by 25 = 2800 rs

i hope the answer is correct!!!

Answered by luckysawa
1

4x×3x=12x×x n x×x=768÷12 or x=8.....so 4x+4x+3x+3x=14x...n hence periphery of rectanvular ground will be=14×8=112m...so cost will be=112×25=2800rs

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