Find the cost of fencing a rectangular park of length 0.8 km and breadth 0.2 km at the rate of 12 per m.
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Given :
- Length of rectangular park = 0.8 km
- Breadth of rectangular park = 0.2 km
To Find :
- Cost of fencing rectangular park at the rate of Rs. 12 per m?
Solution :
Firstly converting units of length and breadth from km to m. As we know that;
- 1 km = 1000 m
So length and breadth in m will be;
➻ Length in m = 0.8 × 1000
➻ Length in m = 8 × 100
➻ Length in m = 800 m
➻ Breadth in m = 0.2 × 1000
➻ Breadth in m = 2 × 100
➻ Breadth in m = 200 m
- Hence, length and breadth in 'm' are 800 m and 200 m.
Now lets find perimeter of rectangular park by using formula of perimeter of rectangle, then we will able to find cost of fencing, As we know that,
- Perimeter of rectangle = 2(l + b)
Where,
- l denotes length of rectangle
- b denotes breadth of rectangle
We have,
- Length (l) = 800 m
- Breadth (b) = 200 m
Putting all values in formula we get,
➻ Perimeter = 2(800 + 200)
➻ Perimeter = 2(1000)
➻ Perimeter = 2 × 1000
➻ Perimeter = 2000 m
- Hence, perimeter of rectangular park is 2090 m.
Now,
➻ Cost = Rate × Perimeter
➻ Cost = 12 × 2000
➻ Cost = Rs. 24000
- Hence, cost of fencing rectangular park at the rate Rs. 12 per m is Rs. 24000.
Know more,
- Perimeter of any figure is calculated by sum of its all sides.
- Perimeter of square = 4 × side
- Area of square = (side)²
- Perimeter of equilateral ∆ = 3 × side
- Area of equilateral ∆ = √3/4 (side)²
- Perimeter of rhombus = 4 × side
- Area of rhombus = ½ × d₁ × d₂
- Perimeter of circle = 2πr
- Area of circle = πr²
- Perimeter of rectangle = 2(l + b)
- Area of rectangle = l × b
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