Question

Find the cost of fencing a rectangular park of length 175 m and breadth 125 m at the rate of ₹ 12 per meter ?​

Answer 1

Step-by-step explanation:

$given -$

length =175m

breadth =125m

the rate fencing per m is equal to RS 12

find that -

cost of fencing of rectangular park

by the question-

Perimeter of the rectangular park = 2(l+b)

= 2(175+125) m

= 2(300) m

= 600 m

Cost of fencing = 600 × ₹12 = ₹7200

∴ ₹7200 is the cost of fencing the rectangular park.

$i \: hope \: its \: help \: you$

Answer 2

Given, a rectangular park of length 175 m and breadth 125 m at the rate of ₹ 12 per meter.

☯we need the cost of fencing.

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\setlength{\unitlength}{0.78 cm}\begin{picture}(12,4)\thicklines\put(5.6,9.1){ A }\put(5.5,5.8){ B }\put(11.1,5.8){ C }\put(11.05,9.1){ D }\put(4.5,7.5){\sf\large{125 \:m\;}}\put(8.1,5.3){\sf\large{175 \:m}}\put(11.5,7.5){\sf\large{125 \:m}}\put(8.1,9.5){\sf\large{175 \:m}}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\end{picture}$

$\star\;{\boxed{\sf{\pink{Perimeter_{(rectangle)}=2(l+b) \;}}}}$

In which,

• l and b are length and breadth of rectangle respectively.

$:\implies\sf 2(175+125)$

$:\implies\sf 2 \times 300$

$:\implies{\boxed{\frak{\purple{600\;m.}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;the\:perimeter \:of\;the \;rectangle \:is\;600\;m.}}}$

$\star\;{\boxed{\sf{\pink{Cost\:of\;fencing = Rate \times Perimeter \;}}}}$

$:\implies\sf 12 \times 600$

$:\implies\sf Rs.\; 7200$

$:\implies{\boxed{\frak{\purple{Rs.\;7200}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;the\:cost \:of\;fencing \:a\;rectangular \;park\:is\;Rs\;7200\;.}}}$

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\qquad\qquad\boxed{\underline{\underline{\bigstar \: \bf\:More\:to\:know\:\bigstar}}}$

$\begin{gathered}\boxed{\begin{minipage}{6 cm}\bigstar \:\underline{\textbf{Some Important Formulae:}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} {Perimeter of rectangle = 2(length + breadth)}\\\\ \sf {\textcircled{\footnotesize\textsf{2}}}Area of rectangle = length \times\ breadth\\\\\sf{\textcircled{\footnotesize\textsf{3}}}Area \: of \: square = (side)^2\\\\ \\{\textcircled{\footnotesize\textsf{4}}}Perimeter\: of\: square = 4 \times\ side\end{minipage}}\end{gathered}$