Hello can you pls help with this question. I need the steps of construction and justification for the same question.
Construct a triangle ABC in which AB = 5.8cm, BC + CA = 8.4cm and ∠B = 60°
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Step-by-step explanation:
1. Draw a line segment AB of length 5.8cm.
2. Draw a line segment BX, sufficiently large such that ∠ABX=60°.
3. From the segment BX, cut off line segment BD of length 8.4cm.
4. Join AD.
5. Draw the perpendicular bisector of AD and let it meet BD at C.
6. Join AC.
Then ABC is the required triangle.
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