find the cost of frncing a rectangular lown at Rs 3.50 per metre , if its area is 2160m sqr and the side are in the ratio of 5:3
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Given
Side ratio =5:3
Area =2160m²
Let assume length =5x
Breadth =3x
Area = 5x*3x=15x²
Atq
Area =2160
So
15x²=2160
X²=2160/15
X²=144
![x = \sqrt[?]{144}](https://tex.z-dn.net/?f=x+%3D++%5Csqrt%5B%3F%5D%7B144%7D+ "x = \sqrt[?]{144}")
X=12
Then length =12x5=60m
Breadth =12x3=36m
Perimeter of rectangle =2 (l+b)
=2(60+36)=192m
Fencing cost of 1 m=3.50₹
Fencing cost of 192m=3.50x192=672₹
Side ratio =5:3
Area =2160m²
Let assume length =5x
Breadth =3x
Area = 5x*3x=15x²
Atq
Area =2160
So
15x²=2160
X²=2160/15
X²=144
X=12
Then length =12x5=60m
Breadth =12x3=36m
Perimeter of rectangle =2 (l+b)
=2(60+36)=192m
Fencing cost of 1 m=3.50₹
Fencing cost of 192m=3.50x192=672₹
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