Question

find the cost of painting 15 cylindrical pillars of a building to be painted if the diameter and height if each pillar are 48 cm and 7 metres respectively. Find the cost of painting if the rate ruppes 2 pers sq.m
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Answer 1

Step-by-step explanation:

Answer:

$\begin{gathered}\begin{gathered} Cost\:of \:15\: cylindrical\\pillars = Rs\:396\end{gathered} \end{gathered}$

Step-by-step explanation:

$\begin{gathered}\begin{gathered} Dimensions \:of \: a\\ \:each\: cylindrical\:pillar:\end{gathered} \end{gathered}$

:

$\begin{gathered}\begin{gathered} Diameter (d)=48\:cm\\Radius(r)=\frac{d}{2}\\=\frac{48}{2}\\=24\:cm\\=0.24\:m\end{gathered} \end{gathered} </p><p>$

Height (h)=7\:mHeight(h)=7m

$\begin{gathered}\begin{gathered} Area\: of \: painting \: one \: pillar \\=2\pi rh\end{gathered} \end{gathered}$

$\begin{gathered}\begin{gathered} Area\: of \: painting \: 15\:such \: pillars\\=15\times 2\pi rh\\=15\times 2\times \frac{22}{7}\times 0.24\times 7\\=158.6 \:m^{2}\end{gathered} \end{gathered} </p><p>$

$\begin{gathered}\begin{gathered}Cost\:of\: painting \\1\:m^{2} = Rs\:2.50\end{gathered} \end{gathered}$

$\begin{gathered}\begin{gathered}Cost\:of\: painting \\158.5\:m^{2} = Rs\:2.50\times 158.5\\=Rs\:396\end{gathered} \end{gathered}$

Therefore,

$\begin{gathered}\begin{gathered} Cost\:of \:15\: cylindrical\\pillars = Rs\:396\end{gathered} \end{gathered}$

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