Question

Find the cost of painting the outer surface of 24 oil cotainer at ₹2.50 sq .m. the dimension of each oil contaner being 60cm*40cm*56cm

Answer 1

Answer:

480000 rupees

Step-by-step explanation:

Given------> Dimensions of each oil container being 60cm × 40cm × 56cm and cost of painting is 2.50 rupees .

To find-----> Cost of painting the outer surface of 24 oil container .

Solution------> ATQ,

Length of oil container = 60 Cm

Breadth of container = 40 Cm

Height of container = 56 Cm

Total surface area of container = 2 ( lb + bh + lh )

= 2 ( 60 × 40 + 40 × 56 + 60 × 56 )

= 2 ( 2400 + 2240 + 3360 )

= 2 ( 8000 )

= 16000 Cm²

Outer surface area of 24 oil container

= 24 × 8000

= 192000 Cm²

Cost of painting 1m² area = 2.5 rupees

Cost of painting 24 container outer surface area

= 192000 × 2.5

= 480000 rupees

Answer 2

Answer:

$\because\underline\textsf{ 480,000 Rs }$

$\sf{Given}\begin{cases}\sf{L=60 cm} \\ \sf{B=40cm} \\\sf{H=56cm}\\\sf{Oil containers = rs.2.50}\end{cases}$

$\large\underline\textsf{To Find }$

$\textsf{ the cost of painting the outer surface } \\ \textsf{of 24 oil cotainer at rs. 2.50 sq .m}$

______________________________________

$\star\sf lenght \: of \: container = 60cm$

$\star\sf breadth \: of \: container = 40cm$

$\star\sf hieght \: of \: container = 56cm$

______________________________________

$\large\star\underline\textsf{ Formula Used }$

$\boxed{\sf2(lb + bh + lh)}$

______________________________________

$\huge\underline\textsf{Explantion:- }$

$\leadsto\sf2(60 \times 40 \times 40 \times 56 \times 60 \times 56)$

$\leadsto\sf(2400 + 2240 + 3360)$

$\leadsto\sf2(8000)$

$\leadsto\sf19000cm {}^{2}$

______________________________________

$\textsf{Outer surface area of = 24oil container }$

$\leadsto\sf24 \times 8000$

$\leadsto\sf192000cm {}^{2}$

_________________________________________

$\star\sf{ cost\: of \:1m^2 \:of \:area=2.5rs}$

$\textsf{cost of painting 24 container outer surface are}$

$\leadsto\sf192000 \times 2.5$

$\leadsto\bf480000$