Question

find the cost of painting the outside surface of salid cylinder of diameter 7m amd hight 25m at 8 ruppese square meter​

Answer 1

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radius=d/2

radius=7/2  height=25m cost of painting =Rs/8

Total surface area = 2*pi*r(r+h)

=2*22/7*7/2(7/2+25)

=44/7*7/2( LCM=7/2+50/2)

=44/7*7/2*57/2 (simplification)

=11/1*1/1*57/1

=627sq.m

cost for painting=627*8

=5016Rs.

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Answer 2

Answer:

5016 Rs

Step-by-step explanation:

Painting the solid cylinder = Total Surface Area of cylinder

Given,

height = 25m

diameter = 7m

         i.e.  radius = 3.5m  /  $\frac{7}{2}$ m

Total Surface Area of cylinder = $2\pi r(r+h)$

= $2$ × $\frac{22}{7}$ × $\frac{7}{2}$  ( $\frac{7}{2}$ + $25$ )

= $22$ ( $\frac{7+ 50}{2}$ )

= 11 x 57

=627 $m^{2}$

Cost / square meter = 8

i.e. 627 x 8

= 5016 Rs.

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