Find the cost of plastering the curved surface of a well 8m deep and 21 m is diameter at the rate of Rs 20m^2
Answers
Answered by
1
Answer:
RS. 10560
Step-by-step explanation:
formula=2πrh
answer
2x22/7x21/2x8
22x24
=528m^2
cost = 528x20
=10560
Answered by
6
Answer:
rs.10560
Step-by-step explanation:
h=8m
d=21m
r=21\2m
csa=2 pie r h
=2*22\7*21\2*8
=528m^2
cost of plastering per m^2=rs.20
cost of 528m^2=rs.20*528
=rs.10560
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