Question

Find the cost of plastering the four walls and the floor of a swimming pool which is 22 metre long ,17 metre wide and 4.5 m deep at the rate of Rs.15 per square metre.​

Answer 1

Answer:

The cost of plastering the four walls and the floor of the swimming pool is Rs.10875.

Step-by-step explanation:

The swimming pool has a shape of a cuboid. Given that the swimming pool is 22 meters  long, 17 meters wide and, 4.5 meters deep. That is, we have the measurements,

$length = 22\ m\\width = 17 \ m\\depth = 4.5 \ m$

We need to find the area of the walls and the floor.

The area of the floor  = $length\times width =22\times 17=374 \ m^2$

The area of the walls is equal to the lateral surface area(LSA). So we have

$LSA=2\times depth(length+width)=2\times 4.5\times( 22+17)= 9\times 39 =351 \ m^2$

So the total area $= 351+374= 725\ m^2$

Plastering one square meter costs Rs. 15. Thus the total cost of plastering is,

$Total\ cost=725\times 15=10875$

It will cost Rs. 10875.

Answer 2

$\large\underline{\sf{Solution-}}$

Given that, Dimensions of swimming pool are

Length of swimming pool, l = 22 m

Breadth of swimming pool, b = 17 m

Height of swimming pool, h = 4.5 m

So,

Total area to be plastered of swimming pool is equals to area of four walls and area of floor.

$\rm \: Area_{(swimmimg \: pool \: to \: be \: plastered)} \:$

$\rm \: =  \:Area_{(four \: walls)} \: + \: Area_{(floor)}$

$\rm \: =  \:2(l + b) \times h + l \times b$

$\rm \: =  \:2(22 + 17) \times 4.5 + 22 \times 17$

$\rm \: =  \:9 \times 39 + 374$

$\rm \: =  \:351 + 374$

$\rm \: =  \:725 \: {m}^{2}$

Now, further given that

$\rm \: Cost\:of\:plastering\:1 \: {m}^{2} \: = \: Rs \: 15$

So,

$\rm \: Cost\:of\:plastering\:725 \: {m}^{2} \: = \: 725 \times 15 = Rs \: 10875$

$\rule{190pt}{2pt}$

Additional Information

Formulae of Cube :-

Total Surface Area = 6(side)²

Curved Surface Area = 4(side)²

Volume of Cube = (side)³

Diagonal of a cube = √3(side)

Perimeter of cube = 12 x side

Formulae of Cuboid

Total Surface area = 2 (length x breadth + breadth x height + length x height)

Curved Surface area = 2 (length + breadth) × height

Volume of the cuboid = (length × breadth × height)

Diagonal of the cuboid =√(l² + b² + h²)

Perimeter of cuboid = 4 (length + breadth + height)