find the cost of plastering the inner surface of a well at ₹9.50 per m^2 if it is 21m deep and diameter of its top is 6m
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Answered by
13
21×6=126m
Therefore.
9.50×126=1,197rs
Answered by
17
so it is a cylinder
csa of cylinder=2πrh
bottom of well=πr^2
csa=2x22/7x3x21. (r=6/2)
=396 m^2
bottom=22/7x3x3=28.16
so tsa of well=424.16
cost=424.16x9.5=4029.52
csa of cylinder=2πrh
bottom of well=πr^2
csa=2x22/7x3x21. (r=6/2)
=396 m^2
bottom=22/7x3x3=28.16
so tsa of well=424.16
cost=424.16x9.5=4029.52
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