Question

find the cost of renovating the walls and the floor of a hall that measures 10m×45m××6m if the cost is 48 per square meter.

Answer 1

area of four walls - 660
area of floor - 450
total area- 1110
cost- 53280

Answer 2

Answer:

Rs.53280.

Step-by-step explanation:

Length of hall (l) = 10 m

Width of hall (b) = 45 m

Height of hall (h)= 6 m

Hall is in the shape of cuboid.

Since renovation is done on the walls and the floor of hall.

So, Area to be renovated = Lateral surface area + Area of base

                                          =$2(l+b)h + lb$

                                          =$2(10+45)6 + 10 \times 45$

                                          =$1110 m^2$

Cost of renovating 1 sq.m. = Rs.48

Cost of renovating 1110 sq.m. = $48 \times 1110$

                                                 = $53280$

Hence the cost of renovating is Rs.53280.