Question

Find the cost of sinking a tube well 280m deep having diameter 3m at the rate of Rs. 3.60 per m3 Find the cost of cementing its inner curved surface area at the rate of Rs. 2.50 per m2.

Answer 1

volume of the well=πr^2 h=22/7*3/2*3/2*280...so cost of sinking a tube well=>22/7*3/2*3/2*280*3.60=>Rs.7128...now the cost of cementing its inner curved surface area=2πrh*2.50=>2*22/7*3/2*280*2.50=>Rs.6600

Answer 2

Answer:

The cost of sinking a tube well is Rs.7121.52.

The cost of cementing is Rs.6594.

Step-by-step explanation:

Given : A tube well 280 m deep having diameter 3 m at the rate of Rs.3.60 per m³.

To find : The cost of sinking a tube well and the cost of cementing its inner curved surface area at the rate of Rs. 2.50 per m² ?

Solution :

The height of the well is h=280 m

The diameter of the well is d=3 m

The radius of the well is $r=\frac{3}{2}=1.5\ m$

Volume of the well is $V=\pi r^2h$

$V=3.14\times (1.5)^2\times 280$

$V=1978.2\ m^3$

The cost of sinking = Rate × Volume

$C=3.60\times 1978.2$

$C=Rs.7121.52$

The cost of sinking a tube well is Rs.7121.52.

The inner curved surface area is $CSA=2\pi rh$

$CSA=2\times 3.14\times 1.5\times 280$

$CSA=2637.6\ m^2$

The cost of cementing = Rate × Area

$C=2.50\times 2637.6$

$C=Rs.6594$

The cost of cementing is Rs.6594.