Question

Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4 per m/ 2

Answer 1

Cost of watering a trapezium = 1/2 × (10+25)×15
= 1/2 × 35×15
=
$1 \div 2 \times 35 \times 15 = 262.5$
$262.5 \times 4$
1050

Answer 2

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟

➧ Area of trapezium field
= 1 / 2 ×

(Sum of parallel sides) × (Distance between them area)

➾ 1 / 2 × (10 + 25) × 15
➾ 262.5 m²

➧ New cost,

➾ 4 / m²
➾ 4 × 262.5 m²
➾ 1050 ...✔

_________
Thanks...✊