Question

Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4 per m/ 2

Answer 1

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➧ Area of trapezium field
= 1 / 2 ×

(Sum of parallel sides) × (Distance between them area)

➾ 1 / 2 × (10 + 25) × 15
➾ 262.5 m²

➧ New cost,

➾ 4 / m²
➾ 4 × 262.5 m²
➾ 1050 ...✔

_________
Thanks...✊

Answer 2

HEY THERE!!


Question:

Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4/m².


Method of Solution:

Given: Parallel sides of trapezium are 10cm and 25 cm and perpendicular distance between the parallel sides is 15 cm.

So, Area of trapezium field =1/2(sum of parallel sides) × (perpendicular distance between them)


Area of Trapezium = 1/2(25+10)×(10)

•°• Area of Trapezium =525/2

Now, According to the Question's Statement!

[the rate watering is rupee 4 per m²]

Required Cost =525/2×4

Hence, Required Cost is Rs 1025.