Question

Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4 per m/ 2

Answer 1

Parallel sides=10 cm and 25 cm
Distance between them or height=15 cm
Area of Trapezium
=
$\frac{1}{2} \times (sum \: of \: parallel \: sides) \times height$
$\frac{1}{2} \times (10 + 25) \times 15 \\ \frac{1}{2} \times 35 \times 15 \\ = 262.5 \: {m}^{2}$
Watering per /m=₹4
Total cost=262.5×4=₹1050

Total cost=₹1050

Answer 2

area of trap field=1/2*(0.01+0.25)×0.15
=1/2*0.35*0.15
=0.02625m^2
cost=4*0.02625
=₹0.105