Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4 per m/ 2
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Answered by
3
Parallel sides=10 cm and 25 cm
Distance between them or height=15 cm
Area of Trapezium
=
Watering per /m=₹4
Total cost=262.5×4=₹1050
Total cost=₹1050
Distance between them or height=15 cm
Area of Trapezium
=
Watering per /m=₹4
Total cost=262.5×4=₹1050
Total cost=₹1050
Answered by
7
area of trap field=1/2*(0.01+0.25)×0.15
=1/2*0.35*0.15
=0.02625m^2
cost=4*0.02625
=₹0.105
=1/2*0.35*0.15
=0.02625m^2
cost=4*0.02625
=₹0.105
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