Question

Find the cost of watering a trapezium
field whose parllel sides are 10 cm and 25 cm respactively, the perpandicular distance between them is 15 cm and the rate watering is rupee 4 per m/ 2

Answer 1

⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
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➧ Area of trapezium field
= 1 / 2 ×

(Sum of parallel sides) × (Distance between them area)

➾ 1 / 2 × (10 + 25) × 15
➾ 262.5 m²

➧ New cost,

➾ 4 / m²
➾ 4 × 262.5 m²
➾ 1050 ...✔

_________
Thanks...✊

Answer 2

Solution:

Perpendicular distance between parallel sides (H) = 15 cm

One parallel side of trapezium (A) = 10 cm

Another parallel side of trapezium (B) = 25 cm

Now,

Area => [(a + b)/2]h

=> [(10 + 25)/2 × 15] cm^2

=> [35/2 × 15] cm^2

=> [17.5 × 15] cm^2

=> 262.5 cm^2

Cost Of watering 1 cm^2 area = Rs 4

Cost of watering 262.5 cm^2 area = Rs 1050

Hence , The cost of watering 262.5 cm^2 area of trapezium field is Rs. 1050.