Find the cost of watering a trapezium field whose parllel sides are 10cm and 25cm respactively the perpandicular distance between them is 15cm and the rate of watering is rupee 4 per m/ 2
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area of a trapezium
= 1/2×height(sum of parallel sides )
height=15cm
parallel sides =10cm and 25cm
area of trapezium = 1/2×15 (10+25)
=1/2×15 (35)
=15×35/2
=525/2
=262.5 cm^2
1 metre = 4 rupees
262.5×4
=1050
the cost of watering the field is 1050 rupees.
hope it helps and please mark brainliest
= 1/2×height(sum of parallel sides )
height=15cm
parallel sides =10cm and 25cm
area of trapezium = 1/2×15 (10+25)
=1/2×15 (35)
=15×35/2
=525/2
=262.5 cm^2
1 metre = 4 rupees
262.5×4
=1050
the cost of watering the field is 1050 rupees.
hope it helps and please mark brainliest
jovitha2005:
please mark brainliest
its wrong
no it's correct
its totally correct mate, thanks alot: )
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