Question

Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively, the perpendicular distance between them is 15 cm and the rate of watering is rs 4 per meter square. the one, who answers the first will be marked as best.....

Answer 1

area of the field
= 1/2(10+25)x 15
=1/2 x 35 x 15
=525/2
=262.5 m^2
Now
cost of watering
= 262.5 x 4
= rs 1050

Answer 2

Hi!

______________________________

Hope you will find my answer in the list of brainlest !

Let us Consider height as a distance between the parallel Sides = 15 m

Let Parallel Side of trapezoidal be "a" = 10 m

then the other parallel  Side will be "b " = 25 m

Find the area

A = (a + b/2)*h

=> (10 + 25/2) * 15

=> (35/2) *15

=> 17.5 * 15

=> 262.5 m^2

Find the cost of watering

We have given Cost of watering 1m^2  area = Rs.4

Cost of Watering 262.5 m^2 area

=> 262.5 * 4

=> Rs.1050

____________________________________________

-----------------Happy New Year------------------------------------

#Be Brainly