Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively, the perpendicular distance between them is 15 cm and the rate of watering is rs 4 per meter square.
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=2a+bhA=210m+25mhA=235m15mA=17.5m(15m)A=262.5m2
{262.5m^2}({4m^2}) = Rs 1050262.5m2(4m2)=Rs1050
{262.5m^2}({4m^2}) = Rs 1050262.5m2(4m2)=Rs1050
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