find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively the perpendicular distance between them is 15cm and rate of watering is rs4 per m square
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Considering the distance between parallel sides (h) = 15 METERS
Let one parallel side of the trapezoid be `a` = 10m
Another parallel side be `b` = 25m
The height that is the distance between the parallel sides = 15m
Area = [(a+b)/2]h
= [(10+25)/2 × 15] m²
= [35/2 × 15] m²
= [17.5 × 15]m²
= 262.5 m²
Cost of watering one m² area = Rs 4
Cost of watering 262.5 m² area = Rs 1050
Let one parallel side of the trapezoid be `a` = 10m
Another parallel side be `b` = 25m
The height that is the distance between the parallel sides = 15m
Area = [(a+b)/2]h
= [(10+25)/2 × 15] m²
= [35/2 × 15] m²
= [17.5 × 15]m²
= 262.5 m²
Cost of watering one m² area = Rs 4
Cost of watering 262.5 m² area = Rs 1050
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