Question

find the cost of watering a trapezoidal field whose parallel sides are 10m and 25m respectively, the perpendicular distance between them is 15 cm and rate of watering is RS 4/m^2.

(at
first ,
find the area of trapezium by converting the ll sides in cm
nd then convert it into m, then I may mark u as brainiest.)
happy New year guys.

Answer 1

given,parallel sides are.10m and 25m perpendicular distance=15cm=0.15m
so area of ||gm=1/2(sum of ||sides)perpendicular distance
=1/2(10+25)0.15=2.625sq.m
as rate of watering is 4 per m^3
so total rate of watering plot=4×2.625=10.5rs
so total rate of watering is 10.5 rupees..
please mark my answer as brainliest...
and please follow me...

Answer 2

Hi!

______________________________

Hope you will find my answer in the list of brainlest !

Let us Consider height as a distance between the parallel Sides = 15 cm

Let Parallel Side of trapezoidal be "a" = 10 m

then the other parallel  Side will be "b " = 25 m

Find the area

A = $(\frac{a + b}{2} )h$

=> $\frac{10 + 25}{2} * 15$

=> $\frac{35}{2} * 15$

=> 17.5 * 15

=> 262.5 m^2

Find the cost of watering

We have given Cost of watering 1m^2  area = Rs.4

Cost of Watering 262.5 m^2 area

=> 262.5 * 4

=> Rs.1050

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