find the cost of whitewashing a room of dimension 6 m into 4.8 m into 4.2 including the ceiling at the rate of rupees 25 per meter
Answers
Answered by
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Given: l-6m;b-4.8m;h-4.2m
Solution:
Area of the room that has to be whitewashed=the total surface area of the room(TSA).
TSA of rectangle=2(lb+bh+hl)
TSA=2(6×4.8+4.8×4.2+4.2×6)
=2(28.8+30.16+25.2)
=2(84.16)
=168.32m^2(TSA of room)
Cost of whitewashing=₹25/m^2
So,cost of whitewashing the room=TSA of the room ×₹25/m^2
=>168.32×25=₹4208
Therefore,the cost of whitewashing the room is ₹4208
kifathi88:
ur answer is wrong first find area of 4wallzs 2h,(l+b) then ceiling l*bthen add it correct answer is 2988
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36
hope it helps you ...........
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