find the cube (3x/2+1)³
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Answer:
Step-by-step explanation:
=\frac{27x^3+54x^2+36x+8}{8}
Step-by-step explanation:
Given Equation is (3x/2 + 1)³
We know that (a + b)³ = a³ + 3a²b + 3ab² + b³
=(\frac{3x}{2})^3+3(\frac{3x}{2})^2*1+3*\frac{3x}{2}*1^2+1^3
=\frac{27x^3}{8}+\frac{27x^2}{4}+\frac{9x}{2}+1
=\boxed{\frac{27x^3+54x^2+36x+8}{8}}
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Answer:
Step-by-step explanation:
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