find the cube by column method 45 and 18?
Answers
We have:
and
We have to find the cube of and 18 by column method.
Solution:
Here two digits are 4 and 5
a = 4, and b = 5
By using the column-method:
Column I Column II Column III Column IV
64 240 300 125
+27 = 91 + 31 = 271 + 12 = 312 5
91 1 2 5 91,125
∴ = 91,125
Thus, the cube of by column method is 91, 125.
Here two digits are 1 and 8
a = 1, and b = 8
By using the column-method:
Column I Column II Column III Column IV
1 24 192 512
+ 4 + 24 =48 + 51 = 243
5 8 3 2 5,832
∴ = 5,832
Thus, the cube of by column method is 5,832.
Answer:
Step-by-step explanation:
cube by column method 45 and 18.
(a) 45
a =4 , b= 5
a³ 3a²b 3ab² b³
64 240 300 125
27 31 12
91 1 2 5
45³ = 91125
(b) 18
a =1 , b =8
a³ 3a²b 3ab² b³
1 24 192 512
4 24 51
5 48 243
5 8 3 2
18³= 5832