Question

find the cube of 2x+3y....please fast and correct answer please..​

Answer 1

$(2x+3y)^3 \\ \\ (2x)^3+(3 \times (2x)^2 \times 3y)+(3 \times 2x \times (3y)^2)+(3y^3) \\ \\ 8x^3+(9y \times 4x^2)+(6x \times 9y^2)+27y^3 \\ \\ 8x^3+36x^2y+54xy^2+27y^3$

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