Question

find the cube of 3a - 2b​

Answer 1

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Answer 2

compare it with

${(x - y)}^{3}={x}^{3} + {y}^{3} - 3 {x}^{2}y + 3{y}^{2}x$

then

x = 3a

y = 2b

then new formula

${(3a - 2b)}^{3}={(3a)}^{3} + {(2b)}^{3} - 3 ({3a})^{2}(2b) + 3{(2b)}^{2}(3a)$

after simplifying

${(3a - 2b)}^{3} = {27a}^{3} + 8 {b}^{3} - 27 {a}^{2} b + 12 {ba}^{2}$

:)