Question

Find the cube of 5 by expressing as sum of consecutive odd no.

Answer 1

Answer:

Let 5 consecutive odd numbers=2n+1,2n+3,2n+5,2n+7,2n+9

given the sum of consecutive numbers =5cube

=125

2n+1+2n+3+2n+5+2n+7+2n+9=125

10n+25=125

10n=125-25

10n=100

n=100/10

n=10

cube of 5 by expressing as sum of consecutive odd no.=21,23,25,27,29