find the cube of (7x +4)
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Answer:
343x^3+64+196x^2+112x
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Answer:
(7x+4)³
=(7x)³+(4)³+3(7x)²(4)+3(7x)(4)²
=343x³+16+588x²+336x
=343x³+588x²+336x+16
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