Question

find the cube root by prime factorization method
a- 216
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Answer 1

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

To Find:

• Cube Root of 216

Solution:

$\\ \Large{ \begin{array}{c|c} \tt 2 & \sf{216} \\ \cline{1-2} \tt 2 & \sf {108} \\ \cline{1-2} \tt 2 & \sf{54} \\ \cline{1-2} \tt 3 & \sf{27 }\\ \cline{1-2} \tt 3 & \sf{ 9 }\\ \cline{1-2} \tt 3 & \sf{3} \\ \cline{1-2} & \sf{ 1} \end{array}} \\ \\ \implies 216 = 2*2*2*3*3*3 \\ \implies 216 = 2^3*3^3 \\ \implies 216 = (2*3)^3 \\ \implies 216 = 6^3 \\ \bold{\implies \sqrt[3]{216} = \sqrt[3]{6^3} = 6}$

Hope it helps!!!

Answer 2

Required Answer:

• Refer to the attachment.!

hope this helps !!