Question

find the cube root of 27

Answer 1

$= \sqrt[3]{27} \\ = \sqrt[3]{ {3}^{3} } \\ = 3$

Answer 2

$\sqrt[3]{27} \\ = {27}^{ \frac{1}{3} } \\ = ( {3}^{3} )^{ \frac{1}{3} } \\ = {3}^{3 \times \frac{1}{3} } \\ = {3}^{1} \\ = 3 \: is \: the \: answer$