Question

Find the cube root of the following numbers by prime factorization methord: [i] 175616 [ii] 91125 Please answer fast............

Answer 1

Answer:

prime factorization is in the attachments]

i)  64 = 2 x 2 x 2 x 2 x 2 x 2

= 2³ x 2³

³√64 =   2×2=4

ii) 512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

= 2³x 2³ x 2³

³√512 =   2×2×2=8

iii)  10648 = 2 x 2 x 2 x 11 x 11 x 11

= 2³ x 11³

³√10648 =   2×11=22

iv)  27000 = 2 x 2 x 2 x 3 x 3 x 3 x 5 x 5 x 5

= 2³ x 3³ x 5³

³√27000 =   2×3×5=30

v) 15625 = 5 x 5 x 5 x 5 x 5 x 5

= 5³x 5³

³15625 =   5×5=25

vi) 13824 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3

= 2³x 2³ x 2³ x 3³

³√13824 =   2×2×2×3=24

vii) 110592 = 2³ x 2³ x 2³ x 2³ x 3³

³√110592 =   2×2×2×2×3=48

viii) 46656 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3

= 2³ x 2³ x 3³x 3³

³√46656 =   2×2×3×3=36

ix) 175616 = 2³x 2³ x 2³ x 7³

³√175616 =   2×2×2×7=56

x) 91125 = 5³ x 3³ x 3³

³√91125 =   5×3×3=45

mark it as branlist

..follow me pls..

Answer 2

Answer:

1 ) 56

2) 45

Step-by-step explanation:

Hope it helps