Question

find the sum and product of the zeros of quadratic polynomial x square - 3​

Answer 1

Explanation:

${x}^{2} -3 = 0 \\ {x}^{2} + 0x - 3 = 0 \\ a = 1 \\ b = 0 \\ c = - 3 \\ \alpha + \beta = \frac{ - b}{a} \\ \alpha + \beta = - \frac{0}{1} \\ \alpha + \beta = 0$

$\alpha \beta = \frac{c}{a} \\ \alpha \beta = \frac{ - 3}{1 } \\ \alpha \beta = - 3$

Answer 2

Explanation:

please explain step by step with good explanation