Question

Find the cubes of the following numbers writing the results using exponent .i) -48



pls help​

Answer 1

Hope it helps your answer in this photo

Answer 2

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

The prime factorization of 48 is 2 × 2 × 2 × 2 × 3, hence, the cube root of 48 in its lowest radical form is expressed as 2 ∛6.

$\sqrt[3]{48} \: \: \: \: \: \: \: = \sqrt[3]{(2× 2 ×2)×2×3}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \sqrt[3]{6}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \huge{\boxed{3.634}}$

Hope It'll Helps!