find the cubic polynomial its zeros are 6, - 5 and 2 respectively
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To find a cubic polynomial by its zeroes, we need 3 things.
1) Sum of all zeroes.
2) Sum of all zeroes multiplied to 1 another zero.
3) Product of zeroes.
Let's do it.
1) Sum of zeroes = 6 + ( -5 ) + 2
= 6 - 5 + 2
= 8 - 5
= 3.
2) Sum of all zeroes multiplied to 1 another zero .
= { 6 x ( - 5 ) } + { ( - 5 ) x 2 } + ( 6 x 2 )
= -30 + ( - 10 ) + 12
= -30 - 10 + 12
= -40 + 12
= -28
3.) Product of zeroes.
= 6 x ( -5 ) x 2
= -60.
Formula for a cubic polynomial is :
= x³ - ( Sum of zeroes ) x² + ( Sum of all zeroes multiplied to 1 another zero )x - Product of zeroes
= x³ - ( 3 ) x² + ( -28 ) x - ( - 60 )
= x³ - 3x² - 28x + 60.
So, required polynomial is ( x³ - 3x² - 28x + 60 ).
1) Sum of all zeroes.
2) Sum of all zeroes multiplied to 1 another zero.
3) Product of zeroes.
Let's do it.
1) Sum of zeroes = 6 + ( -5 ) + 2
= 6 - 5 + 2
= 8 - 5
= 3.
2) Sum of all zeroes multiplied to 1 another zero .
= { 6 x ( - 5 ) } + { ( - 5 ) x 2 } + ( 6 x 2 )
= -30 + ( - 10 ) + 12
= -30 - 10 + 12
= -40 + 12
= -28
3.) Product of zeroes.
= 6 x ( -5 ) x 2
= -60.
Formula for a cubic polynomial is :
= x³ - ( Sum of zeroes ) x² + ( Sum of all zeroes multiplied to 1 another zero )x - Product of zeroes
= x³ - ( 3 ) x² + ( -28 ) x - ( - 60 )
= x³ - 3x² - 28x + 60.
So, required polynomial is ( x³ - 3x² - 28x + 60 ).
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