Question

find the cubic polynomial whose zeroes are -7,1,2,

Answer 1

The polynomial with roots A,B and C is

(x-A)(x-B)(x-C) = [x-(-7)](x-1)(x-2)

                      = (x+7)(x²-3x+2)

                     = (x³-3x²+2x+7x²-21x+14)

                     = (x³+4x²-19x+14)